Sodium thiosulfate reacts with dilute sulfuric acid to yield sodium sulfate (aq), sulfur (solid), sulfur dioxide (gas) and water. The reactions are as follows:

1. Sodium thiosulfate in the solid form is pentahydrate, i.e. Na₂S₂O₃ : 5H₂O(s)
When dissolved in water, you get

Na₂S₂O₃ : 5H₂O 2Na⁺ (aq) + S₂O₃^2- (aq) + 5H₂O(l)

2. Sulphuric acid dissolved in water is

H₂SO₄(l) 2H⁺ (aq) + SO₄^2- (aq)

3. The thiosulfate anion reacts with the hydrogen ion (from sulfuric acid) to produce sulfur, sulfur dioxide and water:

S₂O₃^2- (aq) + 2H⁺ (aq) S(s) + SO₂ (g) + H₂O (l)

4. Hence the net reaction is

Na₂S₂O₃ : 5H₂O(s) + H₂SO₄ 2Na ⁺ (aq) + SO₄ ^2- (aq) + S(s) + SO₂(g) + 6H₂ O (l)

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