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I'm sorry if I confused you about the calculations with the force on the magnet. It turns out that they are inccorect. They are not compatable with the second question I asked you, about the formula to calculating the diamagnetic force created by bismuth. So, if you can direct me to any information or if you have a formula that I can use to calculate the diamagnetic force created by bismuth it would be a big help. I was wondering if I could modify a formula for calculating magnetic force and use that for bismuth, but you guys know more than I do, I would really appreciate the help. So, I guess my question is to put it simply, What is the formula for calculating the diamagnetic force created by bismuth? (at certian points in space taking into acount the magnet and its certian properties, the bismuths properties, etc...)
Question Date: 2008-06-16
Answer 1:

Unfortunately, this issue of calculating magnetic force is quite difficult to do since it traditionally requires knowledge of some quantum mechanics as well as some hefty numerical integration depending on the geometry.

I would recommend (for someone of your likely mathematical standing) to consider the case where the magnet is approximately the same size as the bismuth, and to calculate the diamagnetic force caused by the bismuth, you can use the magnetic susceptibility of bismuth to calculate the induced counter-magnetic field in bismuth.

The magnetic susceptibility of bismuth is about -1.66*10 (-4).

Then you can approximate the force that each of them experience to be the force between two magnets with different magnetization. However, note that they are of constant ratio, since the magnetic susceptibility of bismuth fixes that particular quantity.

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