|Are you sure that the formula for diamagnetic
force (B2/z=mu_0*p*g/x) is correct? I
just want to be 100% sure so I can accurately
calculate the force for the experiment, I don't
want to do the experiment and find out that it
was incorrect. Maybe I'm thinking this because
you said you simplified it a little bit, and it
seems like something is missing. If it is
possible, I would like to know the unsimplifed
version also, even if it is more complex. Then I
could decide if it is within my knowledge to do,
and I could also compare results from the simpler
version of the formula. Thanks for your help,
you've helped me a lot.
Since that's a simplification, it's not totally
correct, but I think(and hope) that it's close
enough to be correct for your experiment. The full
equation is this:B * dB/dz=mu_0 * p * g /
You can see that the only thing that
changed is the left hand side, and I replaced
B2 / z with B * dB/dz. dB/dz
is something from calculus.It's basically how
fast B changes with respect to z.
For example, if Bgoes from 5 T to 10 T in 5
meters, then dB/dz would be approximately
1T/m (Tesla per meter) over that distance. I say
approximately because the magnetic field could
change in a funny way, really fast at first,then
slower later, so it could be different for
different parts of z. But this would be the
correct average value of dB/dz. And that's
basically where the approximation comes in to
play. In the simplified equation, I approximated
dB/dz with B/z, which would roughly
be the average value of dB/dz.
simplified version should be enough if you want to
find a rough value of the minimum magnetic field
strength needed to levitate some Bismuth. If you
were to try to compare the simplified version to
the non-simplified equation, that could be tricky,
because measuring dB/dzwould probably need
a lot of measurements, and I think the tools to
measure a magnetic field can be a bit expensive.
However, it might be possible that wherever you
buy your magnets from would have information on
dB/dz (the rate of change of the magnetic
field with respect to distance) for each magnetic.
I'm not too sure about that, but it mightbe worth
a shot. Good Luck!!
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