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In the alpha decay of Radon-222, what happens to
the electrons? An alpha particle is a helium
nucleus with the positive charge of two,but the
equation in our text book doesn't account for the
electrons...
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Question Date: 2002-11-22 | | Answer 1:
Well, that's a sharp observation of yours! What
happens is that your book depicts the NUCLEAR
reaction, the main realm of nuclear physics, and
believe it or not, electrons, I mean, the electrons
that orbit around the nucleus (because there can
be electrons coming from within the nucleus, as in
beta decay), are of no great concern to nuclear
processes. That's why you most probably see the
alpha particle as superscript 4, subscript 2 He,
without indication of the 2+ charge. But we know
well that charge is conserved in all processes
observed so far, so if you want to be really
rigorous, you can represent your alpha particle as
a 2+ ion and the superscript 188 subscript 84 Po
as a 2- ion (well, that is a likely oxidation
state for polonium, anyways).
When you
study nuclear reactions in general, there is
little information or concern about the chemical
state of the radioactive isotopes (that means
about the external orbiting electrons of these
atoms), because they practically have no influence
on the nuclear behavior.
By the way, I am
right now doing some experiments in which I use
resonant nuclear gamma absorption to study the
chemical state of the absorbing nucleus, this is
called Moess Bauer spectrometer, and I
should say
this is the exception among all techniques that
deal with nuclear processes, for the great amount
of chemical information(again, about electrons in
outer shells) it gives.
Keep those
discerning eyes wide open! | | Answer 2:
This is a great question! When you write CHEMICAL
equations for the creation of compounds from
elements or the dissociation of compounds into
elements, you are writing equations that are
totally based on the sharing and exchanging of
electrons. These reactions always must obey the
laws of conservation of mass and conservation of
electric charge.
But when you write NUCLEAR
equations, involving the particles the
nucleus(protons, neutrons, and their constituent
quarks), these reactions have to do with
instabilities within the nucleus itself, and don't
involve the electrons in the electron
cloud. Nuclear reactions must obey the
conservation
of mass and electric charge, but also must obey
other conservation laws: conservation of baryon
number, lepton number, and still others when you
write equations that govern the particles inside
the particles (quarks).
Alpha particles,
which as you correctly state are helium nuclei
with 2 protons and 2 neutrons don't simply "hang
out" as helium nuclei inside a nucleus of Radon,
for example. The nucleons are always jiggling
around and regrouping. When a He grouping happens
to be near the surface of the nucleus, there is a
certain probability that it will repel from the
nucleus.
Now - what happens if you leave a
substance that decays by alpha decay in a sealed
box is that, after some time, you will find
neutral helium gas inside the box! How did that
neutral helium gas form? When the alpha particles
were ejected from the nucleus they had to go
through the electron cloud and they naturally
picked up a -2 charge from the electron "cloud" to
balance their +2 charge, so that later when you
test the air inside the box you find an
appropriate amount of neutral helium
gas.
Your book did not write this in their
nuclear equations, because the electrons from the
electron cloud are not directly involved in the
nuclear reaction that converts 86-Ra-222 to
84-Po-220, as that is a nuclear reaction. But,
that is what becomes of the extra electrons -
AFTER the alpha particle leaves the nucleus it
attracts the -2 charge from the electron cloud to
make neutral helium gas.
| | Answer 3:
Generally, radioactive decay energies are far in
excess of those needed for electron ionization of
small nucleus such as He. You are correct that the
electrons no longer balance and so two of them
will depart the originator, however, the alpha
particle will almost certainly not take them as it
will be scattering with other atoms on is way out
-- and such interactions would rapidly ionize it
anyway. There is another possibility, however,
which is electron capture in the nucleus, sort of
beta decay running backwards to make a proton into
a neutron.
I hope this short answer help.
| | Answer 4:
I think one way to look at this is to ask what
happens to the electrons when a diatomic molecule,
like H2, N2, or
O2 breaks apart. For simplicity,
lets say that a H2 molecule breaks up
into two
hydrogen atoms. So there are two positively
charged protons moving away from each other with
two electrons floating around. Do you think
the two electrons would stay with one of the
protons or would one electron go with each proton?
Why? So what do you think would (eventually)
happen to the two extra electrons that are around
the Polonium nucleus once the alpha particle
shoots off?
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