Answer 1:
Great question! It turns out that most
reactions are more complicated than they appear.
Let's look at an example to understand why:
2 H2O <-> 2 H2 + O2
This reaction describes "water splitting,"
where water is decomposed into the gases hydrogen
and oxygen. The way the reaction is written, one
might think that two water molecules smash into
each other, and out pops an O2 molecule
and two H2 molecules. This is NOT
actually what happens at the atomic level. There
are a lot of intermediate "elementary
steps" that occur between the reactants
(water) and the products (oxygen and hydrogen).
The list of elementary steps looks something like:
(1) ( H20 <-> OH + H ) x2
(happens 2 times separately).
(2) 2OH <-> H2O2
(3) H2O2 <-> HO2 + H
(4) HO2 <-> O2 + H
(5) ( 2H <-> H2 ) x2
(happens 2 times separately).
These steps usually occur on the surface of a
metal catalyst, which makes it possible to
form all the intermediate species, like a single H
atom, which are usually unstable on their own. If
one studies each elementary step, the reaction
rate exponent is equal to the stoichiometry
coefficient. For example the forward reaction rate
for reaction 5 is:
r5 = k5 * [H]2
and the backward reaction rate is:
r(-5) = k(-5) * [H2]
where k5 and k(-5) are rate
constants, [H] is the concentration of H atoms,
and [H2] is the concentration of
diatomic H (molecule).
When we look at the overall reaction:
H2O <-> 2 H2 + O2
and try to write a forward rate expression:
r_tot = k_tot *
[H2O]x
the rate constant, k_tot, and
exponent, x, are going to have complex
dependencies on the rate constants and exponents
of each of the elementary steps. It is very
hard to calculate what the exponent, x, will be
from the elementary steps, so usually it is just
measured.
The reaction quotient on the other hand is
an equilibrium quantity. This means it does
not care about the path that the atoms take to get
from reactants to products. Since the actually
mechanism doesn't matter for the equilibrium
quotient, the stoichiometry coefficients tell
us everything we need to know about how the
reactants and products are related.
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