|What happens if you put hot water into a balloon and then put it over a flame of a candle?|
|Question Date: 2019-12-31|
Eventually the flame would cause the rubber to fail and the balloon would pop. However, this will take much longer when the balloon is filled with water instead of air. Water has a very high heat capacity (especially compared to air). This means, compared to other substances, water can adsorb a lot of energy with little change temperature. Consequently, when the balloon is filled with water, the flame will have to put in much more energy (i.e. be in contact with the balloon for a longer time) to raise the temperature to the point that the rubber will fail.
Most likely, the candle flame will heat up the water even more, generating more steam in the balloon, and making the balloon pop.
Hot water and cold water will be similar, because the temperature of the flame is Much Much higher than the temperature of the water.
Here's a nice link that tells about putting the BOTTOM of the water balloon, and then the SIDE of the water balloon over the candle flame -
Here's an old answer from ScienceLine -
This is basically answered on ScienceLine here. One detail of the question here is that the water is hot, but this mostly means that the water may not take in as much heat and the balloon skin could rupture earlier than if it were filled with cold water.
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